(v^2-8v+12)/(20-5v^2)

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Solution for (v^2-8v+12)/(20-5v^2) equation:


D( v )

20-(5*v^2) = 0

20-(5*v^2) = 0

20-(5*v^2) = 0

20-5*v^2 = 0

-5*v^2 = -20 // : -5

v^2 = 4

v^2 = 4 // ^ 1/2

abs(v) = 2

v = 2 or v = -2

v in (-oo:-2) U (-2:2) U (2:+oo)

(v^2-(8*v)+12)/(20-(5*v^2)) = 0

(v^2-8*v+12)/(20-5*v^2) = 0

v^2-8*v+12 = 0

v^2-8*v+12 = 0

DELTA = (-8)^2-(1*4*12)

DELTA = 16

DELTA > 0

v = (16^(1/2)+8)/(1*2) or v = (8-16^(1/2))/(1*2)

v = 6 or v = 2

(v-2)*(v-6) = 0

((v-2)*(v-6))/(20-5*v^2) = 0

( v-2 )

v-2 = 0 // + 2

v = 2

( v-6 )

v-6 = 0 // + 6

v = 6

v in { 2}

v = 6

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